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January 27, 2015

January 27, 2015

Posted by **dani** on Sunday, May 2, 2010 at 10:23pm.

am I right so far?

f(x)ax^2+bx+c

y=ax^2+bx+c

y=2x^2+2

y=0=>2x^2+2=0

=>2x^2+2=0

ax^2=2,bx=2,c=0

x=b=sqrtb^2+4ac over 2a

x=(2)+sqrt(2)^24(2)(0)over2(2)

x=sqrt4+4over 2

- algebra-Am I right so far -
**bobpursley**, Sunday, May 2, 2010 at 10:35pmNo, No.

2x^2+ 0x + 2

a=2, b=0, c=2

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