can u tell me what formula i should be using to answer this question?
If a stone falls past a bird on a ledge moving at 4 m/s, how fast will the stone be movingjust before it hits the ground below 9 seconds later?
A. 92.2 m/s
B. 48.2 m/s
C. 352.8 m/s
D. 36 m/s
To answer this question, we need to use the formula for acceleration due to gravity. The formula is:
v = u + gt
Where:
v = final velocity
u = initial velocity
g = acceleration due to gravity
t = time
In this scenario, the stone is initially at rest, so the initial velocity (u) is 0 m/s. The stone falls under the influence of gravity, which has an acceleration value of approximately 9.8 m/s^2. The time (t) it takes for the stone to hit the ground is given as 9 seconds.
Plugging the values into the formula:
v = 0 + (9.8 m/s^2) * 9 s
v = 0 + 88.2 m/s
Therefore, the stone's final velocity just before it hits the ground is approximately 88.2 m/s.
None of the answer choices provided match the calculated value, so it seems there might be an error in the options. Please double-check the answer choices or let me know if you need further assistance.