Sunday

April 20, 2014

April 20, 2014

Posted by **Math (URGENT)** on Sunday, May 2, 2010 at 5:21pm.

a. sqrt of 8 = 8^1/2

b. seventh root of 5^2 = 5^2/7

c. sqrt sqrt 6 = ???

d. fourth root of sqrt of 5^3 = ???

Can someone please check my work and help with "c and d"? Thanks.

- Math (URGENT) -
**Cody**, Sunday, May 2, 2010 at 5:42pmc. sqrt sqrt 6 = 6^1/4

d. fourth root of sqrt of 5^3 = (5^3)^1/8

Are these correct?

Note: for "d" do I just leave it like that or can I further simplify?

Thank you.

- Cody -
**MathMate**, Sunday, May 2, 2010 at 5:44pma. and b. are correct

c.

Recall that the (a^b)^c=a^(b*c)

sqrt(sqrt(x))=(x^(1/2))^(1/2)=x^(1/4)

d.

using again (a^b)^c=a^(b*c)

(sqrt(5^3)^(1/4))

=((5^3)^(1/2))^(1/4)

=((5^(3/2))^(1/4)

=5^((3/2)*(1/4))

=5^(3/8)

**Related Questions**

Algebra - SIMPLIFY: ROOT 0F 7 * ROOT OF 14 SIMPLIFY: ROOT OF 1/5 EVALUATE, IF ...

math - determine the area of triangle abc when side ab= square root of x, side ...

algebra - simplify: square root of 5 + square root of 20 - square root of 27 + ...

math calculus please help! - l = lim as x approaches 0 of x/(the square root of...

algebra 2 - Not sure if either one of these answer are correct to simplify the ...

Math(Roots) - sqrt(24) *I don't really get this stuff.Can somebody please help ...

Math - How do you find a square root of a number that's not a perfect square? I'...

Math - Here is the question: Is the product of two irrational numbers always an ...

Algebra - x^1/2 * y^1/6 *z^1/5. We are to use rational exponents to write an ...

Algebra - 1 last square root : Rationalize the denominator 5/sqrt[3]+sqrt[5]= 5*...