Two oxides of lead were separately reduced to metallic lead by heating in a current of hydrogen and the following data obtained :

(i) Mass of yellow oxide taken = 3.45g
Loss in mass during reduction = 0.24g
(ii) Mass of brown oxide taken = 1.227g
Loss in mass during reduction = 0.16g

Show that the above data illustrate the Law of Multiple Proportions!!!

Sorry I didn't understand the concept it will be better if you solve it completely

To show that the data illustrate the Law of Multiple Proportions, we need to analyze the ratios of the elements involved in each reaction. The Law of Multiple Proportions states that when two elements combine to form more than one compound, the ratio of the masses of one element that combines with a fixed mass of the second element can be expressed in small whole numbers.

Let's analyze the data given:

(i) Mass of yellow oxide taken = 3.45g
Loss in mass during reduction = 0.24g

(ii) Mass of brown oxide taken = 1.227g
Loss in mass during reduction = 0.16g

From the data, we can calculate the masses of lead (Pb) and oxygen (O) involved in each reaction.

For the yellow oxide:
Mass of Pb = Mass of yellow oxide taken - Loss in mass during reduction
= 3.45g - 0.24g
= 3.21g

Mass of O = Loss in mass during reduction
= 0.24g

For the brown oxide:
Mass of Pb = Mass of brown oxide taken - Loss in mass during reduction
= 1.227g - 0.16g
= 1.067g

Mass of O = Loss in mass during reduction
= 0.16g

Now, let's calculate the ratios of Pb and O for each oxide:

(i) For the yellow oxide:
Ratio of Pb to O = Mass of Pb / Mass of O
= 3.21g / 0.24g
= 13.38

(ii) For the brown oxide:
Ratio of Pb to O = Mass of Pb / Mass of O
= 1.067g / 0.16g
= 6.67

The ratio of Pb to O in the yellow oxide (13.38) is approximately twice the ratio in the brown oxide (6.67). This supports the Law of Multiple Proportions, which states that the ratio of the masses of one element that combines with a fixed mass of the second element can be expressed in small whole numbers.

Therefore, the given data illustrates the Law of Multiple Proportions.

I did without ur instructions. And got the answer. And i Know the Law of Multipe Proportion

I would determine the moles of Pb and O in each and the formula.

3.45-0.24 = 3.21

moles Pb = 3.21/207.2 = ??
moles O = 0.24/15 = ??
Now fine the ratioi of the moles to each other in small whole numbers. The easy way to do that is to divide the smaller number by itself (thus you get 1.000 for that one), then divide the other number by the same small number. Round to whole numbers to find the ratio.

Do the same for the second compound and note that the ratio of the O, for a fixed amount of Pb, is in the ratio of small whole numbers.

Sorry but we try to help. We don't DO the homework. Go through my detailed instructions as far as you can, show your work, and tell me what you don't understand when you get stuck. I'll help you through it. First, the law of multiple proportions is here. Familiarize yourself with it.

http://en.wikipedia.org/wiki/Law_of_multiple_proportions