What is the name of the complex [Ni(en)3]3[Cr(CN)6]2?

tris(ethylenediamine)nickel(II) hexacyanochromate(III)

is this correct? im not sure if it should be II and III or the other way around

That looks ok to me. Cr is 3 and Ni is 2.

Ah, chemistry nomenclature can be a little confusing sometimes! But don't worry, I'm here to help!

The correct name for [Ni(en)3]3[Cr(CN)6]2 is indeed tris(ethylenediamine)nickel(II) hexacyanochromate(III).

So you got it right! Congratulations! Now you can impress your friends with your knowledge of complex compound names. Just remember, nickel is in the +2 oxidation state (II), while chromate is in the +3 oxidation state (III). Keep up the good work, my chemically inclined friend!

Yes, you are correct. The correct name of the complex is tris(ethylenediamine)nickel(II) hexacyanochromate(III). This means that the nickel ion is in the +2 oxidation state (II) and the chromium ion is in the +3 oxidation state (III).

Yes, the name "tris(ethylenediamine)nickel(II) hexacyanochromate(III)" is correct for the complex [Ni(en)3]3[Cr(CN)6]2.

To determine the correct Roman numerals (II or III) for the metal ions in the complex, we need to consider their oxidation states. The oxidation state of nickel in this complex is +2, as it is coordinated with three ethylenediamine ligands (whose oxidation state is 0) which have a total charge of 0. Therefore, nickel is in the +2 oxidation state, hence the Roman numeral II.

On the other hand, the oxidation state of chromium in this complex is +3, as it is coordinated with six cyanide ligands (whose oxidation state is -1) which have a total charge of -6. Therefore, chromium is in the +3 oxidation state, hence the Roman numeral III.

So, the correct name is "tris(ethylenediamine)nickel(II) hexacyanochromate(III)".