Posted by **aymal** on Saturday, May 1, 2010 at 3:51pm.

can you pleaaaaase help me find the area between y=cos(4x) and y=1-cos(4x) 0<=x<=pi/4

i tried to solve it, and i got like : 2*sqrt3+ pi/12

is it right? if not please tell me how can i solve it...i'm really confused

- calculus -
**bobpursley**, Saturday, May 1, 2010 at 4:06pm
Graph it first. See where the curves meet. If they meet at some angle less than PI/4, then you will have to break up the integration (upper-lower)dx into segments 1->meeting point> otherwise you get a "negative" area which will subtract from your area.

- calculus -
**aymal**, Saturday, May 1, 2010 at 4:21pm
i did all that, i found Pi/12

then , i took the integral from 0 to pi/12, and from pi/12 to pi/4

and i got:

integr from 0 to pi/12 cos(4x)-(1-cos(4x) + integ from pi/12 to pi/4 1-cos(4x)-cos(4x)

but i'm not sure if it was right or not...can u check with me please?

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