slope-interpept form of the line satisfying the specified conditions: through (-15, -49) and perpendicilar to 5x+8y=-48
The slope of the given line is -5/8
so the slope of our line is +8/5 and the equation starts
y = (8/5)x + b
but (-15,-49) is on it, so
-49 = (8/5)(-15) + b
-49 = -24 + b
b = -25
equation: y = (8/5)x - 25