Sunday
March 26, 2017

Post a New Question

Posted by on .

When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction

\rm CaCO_3{\it(s)}\rightarrow CaO{\it(s)}+CO_2{\it(g)}
How many grams of calcium carbonate are needed to produce 53.0 L of carbon dioxide at STP?

  • chemistry - ,

    1. CaCO3(s) ==> CaO(s) + CO2(g)

    2. Convert 53.0 L to moles. moles = 53.0/22.4.
    3. Using the coefficients in the balanced equation, convert moles CO2 to moles CaCO3.
    4. Now convert moles CaCO3 to grams. g = moles x molar mass.

  • chemistry - ,

    567.99

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question