Posted by donny on Friday, April 30, 2010 at 9:08pm.
can someone please help me with this problem. i'm doing my review right now and i'm stuck?
Find cos(s + t) given that cos s = 1/3, with s in quadrant 1, and sin t = -1/2, with t in quadrant 4.
trig - Reiny, Friday, April 30, 2010 at 9:20pm
s in I
if cos s = 1/3, then sin s = √8/3
t in IV
if sin t = -1/2, then cos t = √3/2
= cosscost - sinssint
= (1/3)(√3/2) - (√8/3)(-1/2)
=(√3 + √8)/6
trig - donny, Friday, April 30, 2010 at 9:49pm
this is the wrong answer..
trig - Reiny, Friday, April 30, 2010 at 11:02pm
I am 100% sure my answer is right.
What have they got?
Is is (√3 + 2√2)/6 perhaps.
If it is, I will let you think about it.
trig - donny, Friday, April 30, 2010 at 11:27pm
yes, (√3 + 2√2)/6 is the correct answer/form. thank you for your help!
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