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Algebra 2

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Find the solution of the exponential form in terms of logarithms

2^(2x+13) = 3^(x-45)

  • Algebra 2 - ,

    (2x+13) log 2 = (x -45) log 3
    2x(log2 + 13log2 = x(log3) - 45log3
    2x(log2) - x(log3) = -45log3 - 13log2
    x(2log2 - log3) = -45log3 - 13log2
    x = (-45log3 - 13log2)/(2log2 - log3)
    x = -203.17

  • Algebra 2 - ,

    4e^x=91

  • Algebra 2 - ,

    2lnx-2+lny+.25lny

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