(9/5) log base 5 (x) = -1
hint: multiply both sides by 5/9
logbase5 x = -1.8
5^(logbase5 x)=?
im confused from what to do now..where did the 5 in the front come from?
oo ok i got it
To solve the equation (9/5) log base 5 (x) = -1, you need to isolate the variable x. Here's how you can do it:
Step 1: Start by multiplying both sides of the equation by 5/9 to get rid of the coefficient in front of the logarithm:
(9/5) log base 5 (x) * (5/9) = -1 * (5/9)
This simplifies to:
log base 5 (x) = (-5/9)
Step 2: Rewrite the logarithmic equation in exponential form. In general, log base b (x) = y can be written as b^y = x. Applying this to our equation, we have:
5^(-5/9) = x
Step 3: Simplify the right side of the equation:
x = 1 / 5^(5/9)
This is the final solution to the equation (9/5) log base 5 (x) = -1. It represents the value of x that satisfies the given equation.