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math (parabola)

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Hi, the question is: Write the equation of the parabola with vertex(3,-1) and x-intercepts 2 and 4.
I did this:
y=?(x-3)^2-1

How to find the a-value?

Many thanks, and I appreciate any answer!

  • math (parabola) -

    y=a(x-3)^2-1

    x-intercept 2 ----> the point (2,0) lies on it

    0 = a(1) - 1
    a = 1

    y=(x-3)^2-1

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