Posted by **Me** on Friday, April 30, 2010 at 3:50pm.

Hi, the question is: Write the equation of the parabola with vertex(3,-1) and x-intercepts 2 and 4.

I did this:

y=?(x-3)^2-1

How to find the a-value?

Many thanks, and I appreciate any answer!

## Answer This Question

## Related Questions

- math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...
- math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...
- Algebra - I'm trying this again, I'd like the quadratic form, so i can then work...
- algebra - A parabola has x-intercepts at 3 and 7, a y-intercept at -21, and (5,4...
- Algebra - Find the vertex of the functions given below. 1. y=(x-4)(x+2) 2. y=2x^...
- Algebra - The vertex of a parabola represented by f(x)=x^2-4x+3 has coordinates ...
- Algebra - Hiya! I have a function here: y = x^2 - 4x - 32 I have some questions ...
- Alg II/Trig - A parabola has a vertex at (0,0); a horizontal axis; and the point...
- algebra - 6. Find the equation of each parabola described below. a) parabola ...
- ALGEBRA 1 - Please check for me.Without drawing the graph of the given equation ...

More Related Questions