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April 18, 2015

April 18, 2015

Posted by **rai** on Friday, April 30, 2010 at 1:29pm.

1) the graph is the same as that of y=6+9x-6x^2

2)the parabola has a minimum point

3)the gradient of the parabola at x=2 is 0

4)the graphy=2+3x-2x^2crosses the x-axis at the same point as the graph y=6+9x-6x^2

5)the vertex of the parabola is at(1,5)

6)the equation of the axis of symmetery is y=-1

7)the gradient of the parabola is positive when x=0

8)the intercept on the y axis is at y=2

- Parabola Help -
**bobpursley**, Friday, April 30, 2010 at 1:57pmHave you plotted this on your calculator?

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