Posted by jess on Friday, April 30, 2010 at 3:22am.
a) pH = pKa + [(base)/(acid)] will get the pH at the beginning.
b)HAc + OH^- ==> H2O + Ac^-
initial:
HAc = 500 x 0.2 M = 100 millimoles.
OH^- = 0
Ac^- = 500 x 0.3M = 150 millimoles.
change:
OH^- = 20 mL x 1 M = 20 millimoles added
HAc = 100-20
Ac^- = 150 + 20
final:
HAc = 80 millimoles
Ac^- = 170 millimiles
Convert millimoles to concn, substitute into the HH equation above and solve for pH.
4
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