Insert your values for x, y, z, & n into KxFey(C2O4)z·nH2O and provide the correct

coefficients to balance the following equation:
___ Fe(NH4)2(SO4)2·6H2O + ___ H2C2O4 + ___ K2C2O4 + ___ H2O2

___ KxFey(C2O4)z·nH2O + ___ (NH4)2SO4 + ___ H2SO4 + ___ H2O

I can't make heads or tails of this question. Do you have one equation or two? If equations they are, where are the arrows. Is there a difference between the top two lines and the lower two lines?

you need to provide your values for x,y,z and n

Yeah I'm having trouble with this one! If x = 3, y = 1, z = 3, and n = 3... then redox reaction...difficult to say the least.

Dr. Bob, this is one equation where the arrow blongs between the top part of the equation, and the bottom part of the equation. So between ___ H2O2 and ___ KxFey(C2O4)z·nH2O.

To Find X, Y, Z, and N you need the mass percents which are 34.9 %, 11.4 %, 42.7%, and 11.0 % respectively. I know how to calculate the empirical formula but I feel as if I'm doing it wrong. I got K9Fe2(C2)4)5*6H20. I don't think that is correct because I cannot balance the equation properly

i did it perfectly fine,

i don't know wat it means by redox though..

To balance the given equation, we need to determine the correct coefficients for each compound.

Let's start by identifying the elements present in each compound and counting their atoms:

On the left side of the equation:
Fe(NH4)2(SO4)2·6H2O: Contains 1 Fe atom, 8 N atoms, 2 S atoms, and 56 H atoms.
H2C2O4: Contains 2 C atoms and 4 O atoms.
K2C2O4: Contains 2 K atoms, 2 C atoms, and 4 O atoms.
H2O2: Contains 2 H atoms and 2 O atoms.

On the right side of the equation:
KxFey(C2O4)z·nH2O: Needs coefficients for K, Fe, C, O, and H.
(NH4)2SO4: Contains 2 N atoms, 8 H atoms, 1 S atom, and 4 O atoms.
H2SO4: Contains 2 H atoms, 1 S atom, and 4 O atoms.
H2O: Contains 2 H atoms and 1 O atom.

Now let's balance the equation by equating the number of atoms on both sides:

First, let's balance the Fe atoms:
Fe(NH4)2(SO4)2·6H2O: 1 Fe
KxFey(C2O4)z·nH2O: y Fe

To balance Fe atoms, we set the coefficient of Fe(NH4)2(SO4)2·6H2O and KxFey(C2O4)z·nH2O to y. Now we have:

___ Fe(NH4)2(SO4)2·6H2O + ___ H2C2O4 + ___ K2C2O4 + ___ H2O2
= y KxFey(C2O4)z·nH2O + ___ (NH4)2SO4 + ___ H2SO4 + ___ H2O

Next, let's balance the C atoms:
H2C2O4: 2 C
K2C2O4: 2 C
KxFey(C2O4)z·nH2O: z C

To balance C atoms, we set the coefficient of H2C2O4, K2C2O4, and KxFey(C2O4)z·nH2O to z. Now we have:

___ Fe(NH4)2(SO4)2·6H2O + z H2C2O4 + z K2C2O4 + ___ H2O2
= y KxFey(C2O4)z·nH2O + ___ (NH4)2SO4 + ___ H2SO4 + ___ H2O

Next, let's balance the H atoms:
Fe(NH4)2(SO4)2·6H2O: 56 H
H2C2O4: 4 H
(NH4)2SO4: 8 H
H2SO4: 2 H
H2O: 2 H
KxFey(C2O4)z·nH2O: n H

To balance H atoms, we set the coefficient of Fe(NH4)2(SO4)2·6H2O, H2C2O4, (NH4)2SO4, H2SO4, H2O, and KxFey(C2O4)z·nH2O to n. Now we have:

___ n Fe(NH4)2(SO4)2·6H2O + z n H2C2O4 + z K2C2O4 + ___ H2O2
= y KxFey(C2O4)z·nH2O + n (NH4)2SO4 + 2 H2SO4 + 2 H2O

Finally, let's balance the O atoms:
Fe(NH4)2(SO4)2·6H2O: 2 x 4 O = 8 O
H2C2O4: 4 O
K2C2O4: 4 O
H2O2: 2 O
(NH4)2SO4: 4 x 4 O = 16 O
H2SO4: 4 O
H2O: O
KxFey(C2O4)z·nH2O: z x 4 O = 4z O

To balance O atoms, we set the coefficient of Fe(NH4)2(SO4)2·6H2O, H2C2O4, K2C2O4, and KxFey(C2O4)z·nH2O to 4z. Now we have:

___ n Fe(NH4)2(SO4)2·6H2O + z n H2C2O4 + z K2C2O4 + ___ H2O2
= y KxFey(C2O4)z·nH2O + n (NH4)2SO4 + 2 H2SO4 + 2 H2O

Now we have a balanced equation with all the coefficients represented in terms of n and z. The specific values for x, y, z, and n would require additional information or experimental data.