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November 28, 2014

November 28, 2014

Posted by **anonymous** on Friday, April 30, 2010 at 1:55am.

coefficients to balance the following equation:

___ Fe(NH4)2(SO4)2·6H2O + ___ H2C2O4 + ___ K2C2O4 + ___ H2O2

___ KxFey(C2O4)z·nH2O + ___ (NH4)2SO4 + ___ H2SO4 + ___ H2O

- chemistry lab -
**DrBob222**, Friday, April 30, 2010 at 12:02pmI can't make heads or tails of this question. Do you have one equation or two? If equations they are, where are the arrows. Is there a difference between the top two lines and the lower two lines?

- chemistry lab -
**Anonymous**, Tuesday, May 4, 2010 at 2:32pmyou need to provide your values for x,y,z and n

- chemistry lab -
**Corphaus**, Wednesday, May 5, 2010 at 2:38amYeah I'm having trouble with this one! If x = 3, y = 1, z = 3, and n = 3... then redox reaction...difficult to say the least.

- chemistry lab -
**Arrash**, Thursday, July 8, 2010 at 1:09pmDr. Bob, this is one equation where the arrow blongs between the top part of the equation, and the bottom part of the equation. So between ___ H2O2 and ___ KxFey(C2O4)z·nH2O.

To Find X, Y, Z, and N you need the mass percents which are 34.9 %, 11.4 %, 42.7%, and 11.0 % respectively. I know how to calculate the empirical formula but I feel as if I'm doing it wrong. I got K9Fe2(C2)4)5*6H20. I don't think that is correct because I cannot balance the equation properly

- chemistry lab -
**Anonymous**, Tuesday, May 3, 2011 at 2:47ami did it perfectly fine,

i dont know wat it means by redox though..

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