Posted by Tony to PsyDAG on Thursday, April 29, 2010 at 11:07pm.
can you walk me through these
4+x/5 < 8
and
x2/3> 2x + 11
Subtract 4 from both sides.
x/5 < 4
Multiply both sides by 5.
x < 20
Now you try the second inequality.
I tried the second one and did not get
7 which is the answer in the book
and 36 is the answer to the first one. Am I missing some steps. Help

Algebra  Reiny, Thursday, April 29, 2010 at 11:37pm
Not sure if PsyDAG is still on here, but I can see your problem
You meant to type
(4+x)/5 < 8 to get the answer in your book
4+x < 40 after multiplying by 5
x < 404
x < 36
for the second you meant to type
(x2)/3 > 2x + 11
x2 > 6x + 33 after multiplying by 3
x  6x > 35
5x > 35
now divide by 5, which results in the switch of inequality
x < 7
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