Friday
March 24, 2017

Post a New Question

Posted by on Thursday, April 29, 2010 at 8:27pm.

A 0.409 kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 19.5 N/m. The block rests on a frictionless surface. A 0.0500 kg wad of putty is thrown horizontally at the block, hitting it with an initial speed of 2.32 m/s and sticking. How far does the putty-block system compress the spring?

My answer .366 is 10% off. Why/How?

  • Physics - , Thursday, April 29, 2010 at 8:30pm

    How can I possibly know why your answer is off? I have no idea what you did.

  • Physics - , Thursday, April 29, 2010 at 8:33pm

    I did m1v1 /(m1+m2) = vf = .252723

    x = vf(m/k)
    x = .366

  • Physics - , Thursday, April 29, 2010 at 8:35pm

    after getting vf, you need to calculate the KE of the putty/block, and set that equal to the compressed energy in the spring 1/2 k x^2, and solve for x.


    I think you need a tutor, you appear to be totally lost.

  • Physics - , Thursday, April 29, 2010 at 8:36pm

    x = v * sqrt(m/k)

    correct?

  • Physics - , Thursday, April 29, 2010 at 8:39pm

    No.
    Set the KE of the putty/block, set it equal to the max stored energy of the spring, 1/2 k x^2

  • Physics - , Thursday, April 29, 2010 at 8:40pm

    when I set 1/2mv2 equal to 1/2kx2

    I got .366

  • Physics - , Monday, October 19, 2015 at 12:10pm

    make sure you are converting your final answer to meters

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question