chemistry
posted by albee on .
I used 10mL of unknown NaClNaBr mixture titrate with 0.10M silver nitrate solution.
10.15mL of silver nitrate solution is used.
the conc. of NaClNaBr mixture is 8g/dm3
I need to calculate the % composition of the NaClNaBr mixture.

Let X = grams NaCl
Let Y = grams NaBr
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X + Y = 0.08 g. (That's 8 x (10/1000) = ?
moles X + moles Y = M x L or
(X/molar mass NaCl) + (Y/molar mass NaBr) = 0.1 x 0.01015.
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Solve the two equations simultaneously, then
%NaCl = (g NaCl/mass sample)*100 = ??
%NaBr = (g NaBr/mass sample)*100 = ??