Posted by Lauren on Thursday, April 29, 2010 at 10:34am.
I think something is missing here. I don't get the connection between step 1 and step 2 and the final product.
To prepare 200 mL of 2.00 M sodium acetate, you will need 0.2 x 2 = 0.4 mol sodium acetate and that x molar mass = about 33 grams (but you need to go through and do it more accurately).
2) There is no indication of the amount of acetic acid added.
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