Homework Help: Calculus

Posted by sh on Thursday, April 29, 2010 at 4:17am.

Differentiate:
y=ln(x/(2x+3))^(1/2)
y=(1/2)ln(x/(2x+3))
y'=0+(1/2)((2x+3-2x)/(2x+3)²)

What's next after the quotient rule?

Calculus - drwls, Thursday, April 29, 2010 at 5:36am
You don't have to use the quotient rule of differentiation.

y = lnx - (1/2)ln(2x+3)
y' = 1/x -(1/2)[1/(2x+3)]*2
= (1/x) - [1/(2x+3)]
which can be rewitten with a common denominator, if you wish.
Calculus - sh, Thursday, April 29, 2010 at 10:47am
Thanks for your help!

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