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**sh** on
.

Differentiate:

y=ln(x/(2x+3))^(1/2)

y=(1/2)ln(x/(2x+3))

y'=0+(1/2)((2x+3-2x)/(2x+3)²)

What's next after the quotient rule?

Tuesday

March 28, 2017
Posted by
**sh** on
.

Differentiate:

y=ln(x/(2x+3))^(1/2)

y=(1/2)ln(x/(2x+3))

y'=0+(1/2)((2x+3-2x)/(2x+3)²)

What's next after the quotient rule?

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