Tuesday
December 6, 2016

Homework Help: Calculus

Posted by sh on Thursday, April 29, 2010 at 4:17am.

Differentiate:
y=ln(x/(2x+3))^(1/2)
y=(1/2)ln(x/(2x+3))
y'=0+(1/2)((2x+3-2x)/(2x+3)²)

What's next after the quotient rule?

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