Posted by Anonymous on Thursday, April 29, 2010 at 12:24am.
Becasue of the inverse swquare law of gravity, the value of g at that orbital altitude will be 1/36 of the value at the earth's surface, which make is g/36. Thus
Centripetal acceleration =
V^2/(6*Re) = g/36
where Re is the radius of the Earth.
V^2 = Re*g/6 = 1.043*10^7
V = 3.32*10^3 m/s
For the orbit period T:
2 pi Re = V*T
T = 1.241*10^4 s = 207 minutes
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