Posted by Anonymous on Thursday, April 29, 2010 at 12:24am.
(a) Find the speed of a satellite moving around the earth in a circular orbit that has a radius equal to six times the earth's radius of 6.38 106 m.
(b) Find the satellite's orbital period.

physics  drwls, Thursday, April 29, 2010 at 5:54am
Becasue of the inverse swquare law of gravity, the value of g at that orbital altitude will be 1/36 of the value at the earth's surface, which make is g/36. Thus
Centripetal acceleration =
V^2/(6*Re) = g/36
where Re is the radius of the Earth.
V^2 = Re*g/6 = 1.043*10^7
V = 3.32*10^3 m/s
For the orbit period T:
2 pi Re = V*T
T = 1.241*10^4 s = 207 minutes
Answer This Question
Related Questions
 Physics  (a) Find the speed of a satellite moving around the earth in a ...
 Physics  (a) Find the speed of a satellite moving around the earth in a ...
 physics  A satellite is in a circular orbit around the Earth at an altitude of ...
 physics  NASA launches a satellite into orbit at a height above the surface of ...
 physics  A 512 kg satellite is in a circular orbit about the Earth at a height ...
 Physics  A satellite is in a circular orbit around an unknown planet. The ...
 Physics 141  A satellite is in a circular orbit around an unknown planet. The ...
 Physics 141  A satellite is in a circular orbit around an unknown planet. The ...
 Physics  A satellite is in a circular orbit around an unknown planet. The ...
 Physics Circular Motion  A satellite in orbit around the earth has a period of ...
More Related Questions