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October 1, 2014

October 1, 2014

Posted by **Anonymous** on Thursday, April 29, 2010 at 12:24am.

(b) Find the satellite's orbital period.

- physics -
**drwls**, Thursday, April 29, 2010 at 5:54amBecasue of the inverse swquare law of gravity, the value of g at that orbital altitude will be 1/36 of the value at the earth's surface, which make is g/36. Thus

Centripetal acceleration =

V^2/(6*Re) = g/36

where Re is the radius of the Earth.

V^2 = Re*g/6 = 1.043*10^7

V = 3.32*10^3 m/s

For the orbit period T:

2 pi Re = V*T

T = 1.241*10^4 s = 207 minutes

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