Posted by **Anonymous** on Thursday, April 29, 2010 at 12:24am.

(a) Find the speed of a satellite moving around the earth in a circular orbit that has a radius equal to six times the earth's radius of 6.38 106 m.

(b) Find the satellite's orbital period.

- physics -
**drwls**, Thursday, April 29, 2010 at 5:54am
Becasue of the inverse swquare law of gravity, the value of g at that orbital altitude will be 1/36 of the value at the earth's surface, which make is g/36. Thus

Centripetal acceleration =

V^2/(6*Re) = g/36

where Re is the radius of the Earth.

V^2 = Re*g/6 = 1.043*10^7

V = 3.32*10^3 m/s

For the orbit period T:

2 pi Re = V*T

T = 1.241*10^4 s = 207 minutes

## Answer This Question

## Related Questions

- Physics - (a) Find the speed of a satellite moving around the earth in a ...
- Physics - (a) Find the speed of a satellite moving around the earth in a ...
- physics - A satellite is in a circular orbit around the Earth at an altitude of ...
- physics - NASA launches a satellite into orbit at a height above the surface of...
- physics - A 512 kg satellite is in a circular orbit about the Earth at a height ...
- Physics - A satellite is in a circular orbit around an unknown planet. The ...
- Physics 141 - A satellite is in a circular orbit around an unknown planet. The ...
- Physics 141 - A satellite is in a circular orbit around an unknown planet. The ...
- Physics - A satellite is in a circular orbit around an unknown planet. The ...
- Physics Circular Motion - A satellite in orbit around the earth has a period of ...

More Related Questions