Saturday

March 28, 2015

March 28, 2015

Posted by **Anonymous** on Thursday, April 29, 2010 at 12:24am.

(b) Find the satellite's orbital period.

- physics -
**drwls**, Thursday, April 29, 2010 at 5:54amBecasue of the inverse swquare law of gravity, the value of g at that orbital altitude will be 1/36 of the value at the earth's surface, which make is g/36. Thus

Centripetal acceleration =

V^2/(6*Re) = g/36

where Re is the radius of the Earth.

V^2 = Re*g/6 = 1.043*10^7

V = 3.32*10^3 m/s

For the orbit period T:

2 pi Re = V*T

T = 1.241*10^4 s = 207 minutes

**Answer this Question**

**Related Questions**

Physics - (a) Find the speed of a satellite moving around the earth in a ...

Physics - (a) Find the speed of a satellite moving around the earth in a ...

physics - Find the speed of a satellite in a circular orbit around the earth ...

Physics - A spy satellite is in circular orbit around Earth. It makes one ...

Physics - A spy satellite is in circular orbit around Earth. It makes one ...

Physics 141 - A satellite is in a circular orbit around an unknown planet. The ...

Physics 141 - A satellite is in a circular orbit around an unknown planet. The ...

physics - 4(a) What is the magnitude of the gravitational force of the Earth on ...

physics - A 512 kg satellite is in a circular orbit about the Earth at a height ...

geometry - A satellite in a nearly circular orbit is 2000 km above Earth's ...