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what is the freezing point of a solution of 12.0 g of CCl4 dissolved in 750.0g of benzene? the freezing point of benzene is 5.48 degrees C ; Kf is 5.12 degrees c/m.

  • chemistry -

    convert 12.0 g CCl4 to moles. moles = grams/molar mass

    molality = moles/kg solvent
    solve for molality

    delta T = Kf*m.
    Solve for delta T and subtract from the normal freezing point of benzene.

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