posted by Kim on .
what is the freezing point of a solution of 12.0 g of CCl4 dissolved in 750.0g of benzene? the freezing point of benzene is 5.48 degrees C ; Kf is 5.12 degrees c/m.
convert 12.0 g CCl4 to moles. moles = grams/molar mass
molality = moles/kg solvent
solve for molality
delta T = Kf*m.
Solve for delta T and subtract from the normal freezing point of benzene.