HELP
the bulldogs won twice as many games as they lost. if yhey played a total of 36 games,how many did they win?
Let x = the number of games they lost.
x + 2x = 36
3x = 36
x = 12
36 - 12 = games won
To find out how many games the bulldogs won, you can set up a system of equations based on the information given. Let's say that the number of games they won is represented by "W," and the number of games they lost is represented by "L."
1. According to the problem, the bulldogs won twice as many games as they lost: W = 2L.
2. The total number of games played is given as 36: W + L = 36.
To solve this system of equations, you can substitute the value of W from equation 1 into equation 2:
2L + L = 36.
Combining like terms:
3L = 36.
Solving for L by dividing both sides of the equation by 3:
L = 12.
Now, substitute the value of L back into equation 1 to find W:
W = 2 × 12 = 24.
Therefore, the bulldogs won 24 games.
To solve this problem, we can use algebra. Let's assume the number of games the bulldogs lost is "x". Since they won twice as many games as they lost, the number of games they won is "2x".
We are also given that the total number of games played is 36. So the sum of games won and games lost is equal to 36:
Games Won + Games Lost = 36
Substituting the values we found earlier:
2x + x = 36
Combine like terms:
3x = 36
Divide both sides of the equation by 3:
x = 12
So the bulldogs lost 12 games. Since they won twice as many games, they won:
2x = 2 * 12 = 24 games
Therefore, the bulldogs won 24 games.