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August 31, 2014

August 31, 2014

Posted by **Jennifer** on Wednesday, April 28, 2010 at 12:54am.

- Math -
**Reiny**, Wednesday, April 28, 2010 at 8:26amx -- as defined

y = 20cosØ

x^2 + y^2 = 400

x^2 + 400cos^2 Ø = 400

2x dx/dØ - 2sinØcosØ = 0

dx/dØ = sinØcosØ/x

when x = π/3 , sinπ/3 =√3/2, cosπ/3 = 1/2

x^2 + 400(3/4) = 400

x = 10

dx/dØ = (√3/2)(1/2)/10 = √3/40

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