Posted by **dani** on Wednesday, April 28, 2010 at 12:45am.

I am totally lost on how to solve

g(x)=2x^2+3x-1 to find the y and x-intercepts.

This is what I have so far, but I don't know if I am on the right track. And if so what would be next?

g(x)=2x^2+3x-1

=2x^2+3x -1

=(2x^2+3+6) +3-1

- algebra -
**Matt**, Wednesday, April 28, 2010 at 1:24am
Get y-intercept when x=0

g(x) = y = 2(0)^2 + 3(0) - 1

(0,-1) ; y-intercept = -1

x-intercept: set function equal to 0

2x^2 + 3x - 1 = 0

After quadratic equation...

x-intercepts: x = -1.78, and x = 0.28

function to the 2nd power of x, so is a parabola opening upwards. Graphing the function verifies the answers.

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