Posted by dani on Wednesday, April 28, 2010 at 12:45am.
I am totally lost on how to solve
g(x)=2x^2+3x1 to find the y and xintercepts.
This is what I have so far, but I don't know if I am on the right track. And if so what would be next?
g(x)=2x^2+3x1
=2x^2+3x 1
=(2x^2+3+6) +31

algebra  Matt, Wednesday, April 28, 2010 at 1:24am
Get yintercept when x=0
g(x) = y = 2(0)^2 + 3(0)  1
(0,1) ; yintercept = 1
xintercept: set function equal to 0
2x^2 + 3x  1 = 0
After quadratic equation...
xintercepts: x = 1.78, and x = 0.28
function to the 2nd power of x, so is a parabola opening upwards. Graphing the function verifies the answers.
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