Posted by Anonymous on Tuesday, April 27, 2010 at 10:23pm.
*simplify by combining like terms, if possible. then, remove the GCF and factor fully.
2x^221x+36+x^2
=3x^221x+36
...i'm not sure what to do after that, could you help and show the steps please

math  Ana, Tuesday, April 27, 2010 at 11:11pm
3x^221x+36 GCF: 3, so divide the whole thing by 3.
x^27x+12
(What two #s add up to 7 and multiplied equal 12? 3 and 4)
[x^24x]  [3x+12]
x(x4)  3(x4)
(x4)(x3)=0
x4= 4 x3= 3 Answer X=3 and 4

math  Reiny, Tuesday, April 27, 2010 at 11:17pm
I thought it said, factor fully.
You had
3x^2  21x + 36 , which is correct
= 3(x^2  7x + 12)
= 3(x4)(x3)
nothing was said about "solving" the equation, since there was no equation.
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