Posted by Anonymous on Tuesday, April 27, 2010 at 10:23pm.
3x^2-21x+36 GCF: 3, so divide the whole thing by 3.
x^2-7x+12
(What two #s add up to -7 and multiplied equal 12? 3 and 4)
[x^2-4x] - [3x+12]
x(x-4) - 3(x-4)
(x-4)(x-3)=0
x-4= 4 x-3= 3 Answer X=3 and 4
I thought it said, factor fully.
You had
3x^2 - 21x + 36 , which is correct
= 3(x^2 - 7x + 12)
= 3(x-4)(x-3)
nothing was said about "solving" the equation, since there was no equation.
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