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July 28, 2014

July 28, 2014

Posted by **Anonymous** on Tuesday, April 27, 2010 at 10:23pm.

2x^2-21x+36+x^2

=3x^2-21x+36

...i'm not sure what to do after that, could you help and show the steps please

- math -
**Ana**, Tuesday, April 27, 2010 at 11:11pm3x^2-21x+36 GCF: 3, so divide the whole thing by 3.

x^2-7x+12

(What two #s add up to -7 and multiplied equal 12? 3 and 4)

[x^2-4x] - [3x+12]

x(x-4) - 3(x-4)

(x-4)(x-3)=0

x-4= 4 x-3= 3 Answer X=3 and 4

- math -
**Reiny**, Tuesday, April 27, 2010 at 11:17pmI thought it said, factor fully.

You had

3x^2 - 21x + 36 , which is correct

= 3(x^2 - 7x + 12)

= 3(x-4)(x-3)

nothing was said about "solving" the equation, since there was no equation.

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