Assume 2.5 grams of benzion and 12.0 mL of 15.8 M nitric acid (density = 1.51 g/mL) was used in the experiment . What is the mole to mole ratio of benzion and nitrate ion.
moles benzoin = grams/molar mass
moles HNO3 = (1.51 g/mL x 12.0 mL)/molar mass,
You can do the ratio.
.0118 moles benzoin
.288 moles HNO3
How do I do the ratio?
If it's the ratio of the moles you have to start with it is just 0.0118/0.288 = ??
It's another ball game if you want the ratio of the REACTING materials.
To determine the mole-to-mole ratio between benzoin and nitrate ion, we need to find the number of moles of each substance.
First, let's calculate the number of moles of benzoin:
Molar mass of benzoin (C14H12O) = 212.25 g/mol
Number of moles of benzoin = mass of benzoin / molar mass of benzoin
= 2.5 g / 212.25 g/mol
≈ 0.0118 mol
Next, let's find the number of moles of nitric acid:
Molarity of nitric acid = 15.8 M
Volume of nitric acid = 12.0 mL = 12.0 cm³
= 12.0 cm³ * (1 mL / 1 cm³)
= 12.0 mL * 1
= 12.0 mL
Number of moles of nitric acid = Molarity of nitric acid * Volume of nitric acid
= 15.8 mol/L * (12.0 mL / 1000 mL/L)
= 0.1896 mol
Now, we can determine the mole-to-mole ratio by comparing the coefficients of benzoin and nitrate ion in the balanced equation.
Since we don't have the balanced equation, I can't provide you with the exact mole-to-mole ratio for benzoin and nitrate ion. However, once you have the balanced equation, you can compare the coefficients of benzoin and nitrate ion to find the ratio directly.
Remember, the mole-to-mole ratio is determined by the stoichiometry of the balanced chemical equation.