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December 19, 2014

December 19, 2014

Posted by **charlotte** on Tuesday, April 27, 2010 at 4:56pm.

- math -
**Reiny**, Tuesday, April 27, 2010 at 5:26pmQuestion:

Do you consider an ace a "picture" card?

I will assume you only want the J, Q, and K

There are 12 of those

So the number of sets of 5 form those 12 = C(12,5)

Without restriction, the number of sets of 5 is C(52,5)

so the prob that your 5 cards are "picture" cards

= C(12,5)/C(52,5) = 792/259860 = .000305

If your interpretation is otherwise make the necessary changes.

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