Posted by charlotte on Tuesday, April 27, 2010 at 4:56pm.
Question:
Do you consider an ace a "picture" card?
I will assume you only want the J, Q, and K
There are 12 of those
So the number of sets of 5 form those 12 = C(12,5)
Without restriction, the number of sets of 5 is C(52,5)
so the prob that your 5 cards are "picture" cards
= C(12,5)/C(52,5) = 792/259860 = .000305
If your interpretation is otherwise make the necessary changes.
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