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March 1, 2015

Posted by **krista** on Tuesday, April 27, 2010 at 3:37pm.

- physics -
**drwls**, Tuesday, April 27, 2010 at 5:54pmGet the velocity of the earth in its orbit from

V = (2 pi R)/P

P is the orbital period, which is one year converted to seconds. R is the Earth's orbital radius.

The centripetal acceleration of the Earth is a = V^2/R.

The force exerted on the Earth by the sun is Me * a

where Me is the mass of the Earth.

- physics -
**mert**, Thursday, July 11, 2013 at 6:45pmA satellite used in a cellular telephone network has a mass of 2010kg and is in a circular orbit at a height of 770km above the surface of the earthWhat is the gravitational force Fgrav on the satellite?

Take the gravitational constant to be G = 6.67×10−11N⋅m2/kg2 , the mass of the earth to be me = 5.97×1024kg , and the radius of the Earth to be re = 6.38×106m .

What fraction is this of the satellite's weight at the surface of the earth?

Take the free-fall acceleration at the surface of the earth to be g = 9.80m/s2 .

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