You meet a person with prescription glasses of +1.74 dpt.

What is the near point of this person? Express the result as a positive number!

Hint: the near point of a healthy person is 25 cm. An object placed at this distance will form an image at the near point of the person.

1.74=-q/p
-q=(25)(1.74)=43.5

i know i'm missing something because the answer is 44.2+/- 0.1 ...am i completely off with the equation and just got a number similar...?

To calculate the near point (also known as the near point of accommodation) for a person with prescription glasses, you need to use the lens formula:

1/f = 1/p - 1/q

Where:
f is the focal length of the lens,
p is the distance of the object placed in front of the lens, and
q is the distance of the image formed by the lens.

In this case, the person's prescription glasses have a power of +1.74 diopters.
The formula for the power of a lens is given by:

Power (P) = 1/f => f = 1/P

Therefore, the focal length (f) of the person's glasses would be:

f = 1/1.74 = 0.574 meter (since the unit of diopters is inverse meter)

Now, in a healthy person, the near point is typically about 25 cm or 0.25 meters. We can use this known value of the near point to find the image distance (q) using the lens formula.

Substituting the given values and solving for q:

1/f = 1/p - 1/q => 1/0.574 = 1/0.25 - 1/q

Simplifying the equation:

1/0.574 = 4 - 1/q

Rearranging the equation:

1/q = 4 - 1/0.574 = 3.741

Taking the reciprocal of both sides:

q = 1/3.741 = 0.267 meter (or 26.7 cm)

So, the near point for a person with prescription glasses of +1.74 diopters is approximately 26.7 cm.