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Posted by on Tuesday, April 27, 2010 at 12:41pm.

What is the decay constant for a radioactive isotope which decreases to 34% of its original value in 2.48 hours?

  • General chemistry - , Tuesday, April 27, 2010 at 12:50pm

    ln(No/N) = kt
    ln(100/34) = k(2.48)
    I started with 100 arbitrarily, then made the N value 34% of that. Solve for k.

  • General chemistry - , Tuesday, April 27, 2010 at 12:55pm

    thank you so much

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