Posted by laney on Monday, April 26, 2010 at 11:48pm.
q = mass x specific heat x delta T.
That's mass H2O x sp.h.H2O x delta T water.
do i use the 5.00 g or the 2.00 * 10^2 g?
ok so it'd be
(2.00*10^2)(6.00 degree C) and then what would be the specific heat?
specific heat of h2o is 4.184
i got 5020.8
i got 5020.8
you have to convert it from joules to calories and idk that off hand but other then that it looks good so far
ok, we didnt do joules in class, so hopefully thats what my teacher wants. thank you!
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