How do you calculate the number of mL you would use to prepare 5.0 L of 0.20 M NaOH from a 5.23 M stock solution.

use the equation drbob222 gave you before. its the right one. you may have to convert the 5 L to mL first though for it to work or understand that ur answer is in L and convert it. one or the other

i got a huge number, is 191.20 correct?

yep

Yes. After all you're making 5,000 mL.

it makes sense too because if you think about it you are making a 5.0 L solution and 191.20 mL isnt even 1/5 of a liter

ok thank you!! i posted a new question! i have a test tomorrow morning and im doing a practice exam and a few questions stumped me!!

To calculate the number of mL needed to prepare the desired solution, you can use the formula:

Volume of stock solution x Concentration of stock solution = Volume of dilute solution x Concentration of dilute solution

Let's substitute the given values into the formula:

(5.0 L) x (0.20 M) = Volume of dilute solution x (5.23 M)

Now we can solve for the volume of dilute solution:

Volume of dilute solution = (5.0 L x 0.20 M) / (5.23 M)

Calculating:

Volume of dilute solution = 0.095 L

Since the desired volume of dilute solution is typically given in mL, we need to convert 0.095 L to mL:

Volume of dilute solution = 0.095 L x 1000 mL/L

Volume of dilute solution = 95 mL

Therefore, to prepare 5.0 L of a 0.20 M NaOH solution from a 5.23 M stock solution, you would need to measure 95 mL of the stock solution and dilute it to the desired volume with the appropriate solvent (usually water) to obtain the desired concentration.