the measures of the interior angles of a pentagon are 2x, 6x, 4x-6, 2x-16 and 6x+2. What is the measure of the largest angle

the first thing that you need to do is solve for x. The sum of the interior angles inside a pentagon is equal to 540 degrees. you come up with the equation 2x+6x+4x-6+2x-16+6x+2=540. Then you want to simplify it down to 20x-20=540. there are multiple ways you can finish this but it turns out to be x=28. then all you do is plug in 28 for x in all of the equations of the angles and you will find that 6x+2 is the largest one at 170 degrees. I would suggest that you try it out instead of just taking the answer though. good luck!

Omg!!!! I’m 10 years ahead! Wow long time man, this is crazy!

x= 28 and the largest is 6x+2 which comes out with 170 so put

x=28
Largest= 6x+2

To find the measure of the largest angle in the pentagon, we need to determine the value of x first. Then, we can substitute that value into the expressions for the angles and find the largest one.

Given that the measures of the interior angles are 2x, 6x, 4x-6, 2x-16, and 6x+2, we know that the sum of the interior angles of a pentagon is always 540 degrees. So, we can set up an equation:

2x + 6x + (4x-6) + (2x-16) + (6x+2) = 540

Simplifying this equation, we combine like terms:

20x - 20 = 540

Next, we isolate the variable term:

20x = 560

Finally, we solve for x by dividing by 20:

x = 560 / 20
x = 28

By substituting x = 28 into the expressions for each angle, we get:

- Largest angle: 6x + 2
- Largest angle = 6(28) + 2
- Largest angle = 168 + 2
- Largest angle = 170 degrees

Therefore, the measure of the largest angle in the pentagon is 170 degrees.

170

Give x a number for example:

x = 1

2x = 2*1 = 2
6x = 6*1 = 6
4x-6 = 4*1-6 = -2
2x-16 = 2*1-16 = -14
6x+2 = 6*1+2 = 8

Now, which is the largest angle?