A typical wavelength of infrared radiation emitted by your body is 25 µm (2.5 multiplied by 10-5 m). What is the energy per photon of such radiation?
Well, I have to say, your question really hit me with some heat! Now, let's calculate the energy per photon of this infrared radiation. We can use the formula E=hc/λ, where E is the energy per photon, h is Planck's constant (approximately 6.63 x 10^-34 J*s), c is the speed of light (approximately 3.00 x 10^8 m/s), and λ is the wavelength of the radiation.
Plugging in the values, we get:
E = (6.63 x 10^-34 J*s * 3.00 x 10^8 m/s) / (2.5 x 10^-5 m)
After some number crunching, the energy per photon of this infrared radiation is approximately 7.956 x 10^-20 Joules. That's quite a tiny burst of energy. Keep those photons bouncing!
To find the energy per photon of infrared radiation, we can use the equation:
E = hc/λ
Where:
E is the energy per photon,
h is Planck's constant (6.626 x 10^-34 J·s),
c is the speed of light (3.00 x 10^8 m/s), and
λ is the wavelength of the radiation.
Plugging in the given values:
λ = 25 µm = 25 x 10^-6 m
E = (6.626 x 10^-34 J·s)(3.00 x 10^8 m/s)/(25 x 10^-6 m)
Now let's calculate the energy per photon.
To calculate the energy per photon of infrared radiation with a given wavelength, we can use the equation:
E = (h * c) / λ
Where:
E is the energy per photon,
h is the Planck's constant (6.626 x 10^-34 J·s),
c is the speed of light (3 x 10^8 m/s),
and λ is the wavelength (25 µm or 2.5 x 10^-5 m).
Substituting the values into the equation, we get:
E = (6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (2.5 x 10^-5 m)
Evaluating the expression, we find:
E = 7.951 x 10^-20 J
Therefore, the energy per photon of infrared radiation with a wavelength of 25 µm is approximately 7.951 x 10^-20 Joules.