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Chemistry

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Why does losing two electrons to form a +2 Cation cause the greatest shrinkage in atomic radius of the following? People are telling me that's the answer but I don't understand.

a. Gaining one electron to form a 1+ cation
b. Losing two electrons to form a 2+ cation
c. Gaining two electrons to form a 2- anion
d. Gaining two electrons to form a 2+ cation
e. Gaining one electron to form a 1- anion
f. Losing one electron to form a 1+ cation

  • Chemistry -

    Losing electrons from an outside shell forms a + charge (cation) AND reduces the size (fewer electrons occupy less space).
    Gaining electrons forms a negative charge (anion) AND increases the size (more electrons occupy a larger space).

    a. Gaining one electron to form a 1+ cation Gaining one electron forms an anion.

    b. Losing two electrons to form a 2+ cation OK

    c. Gaining two electrons to form a 2- anion See above. Gaining electrons increases the size.

    d. Gaining two electrons to form a 2+ cation Gaining two electrons forms a -2 charge

    e. Gaining one electron to form a 1- anion True BUT gaining electrons increases the size.

    f. Losing one electron to form a 1+ cation True and it decreases the size but not as much as losing two electrons.

  • Chemistry -

    Much obliged. I appreciate how you explain how to figure it out, as opposed to just telling me the answer.

  • Chemistry -

    How many electrons are transferred between the cation and anion to form the ionic bond in one formula unit of each compound? LIF, CaS, NaCI, KBr, BaO

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