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January 30, 2015

January 30, 2015

Posted by **Abbey(Please help)** on Saturday, April 24, 2010 at 10:23pm.

s(t)=-16t^2+100, gives the height(in feet) of the paint brush as it falls to the ground. The velocity at time t=2 seconds is given by

lim s(2)-s(t)/2-t

t-->2

Evaluate this limit to find the velocity of the paint brush at 2 seconds. (include units in your answer).

- Math -
**Reiny**, Saturday, April 24, 2010 at 10:48pmagain, you typed it wrong

should be

lim ( s(2) - s(t))/(2-t) as t ---> 2

= lim (36 + 16t^2 - 100)/(2-t)

= lim (16(t^2 - 4)/(2-t)

= lim 16(t+2)(t-2)/(2-t)

= lim 16(-1)(t+2) as t --->2

= 16(-1)(4) = -64

- Math -
**Abbey(Please help)**, Saturday, April 24, 2010 at 10:56pmThank You!!

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