Posted by Abbey(Please help) on .
A painter working at 100 feet from the ground, drops his paint brush onto the street below. The function,
s(t)=16t^2+100, gives the height(in feet) of the paint brush as it falls to the ground. The velocity at time t=2 seconds is given by
lim s(2)s(t)/2t
t>2
Evaluate this limit to find the velocity of the paint brush at 2 seconds. (include units in your answer).

Math 
Reiny,
again, you typed it wrong
should be
lim ( s(2)  s(t))/(2t) as t > 2
= lim (36 + 16t^2  100)/(2t)
= lim (16(t^2  4)/(2t)
= lim 16(t+2)(t2)/(2t)
= lim 16(1)(t+2) as t >2
= 16(1)(4) = 64 
Math 
Abbey(Please help),
Thank You!!