Posted by Maddison on Saturday, April 24, 2010 at 8:17pm.
The intensity varies (changes) as a function of the inverse square. Here is an example.
My superscripts didn't do well. Let me try again.
If the light intensity is simple units is, say, x, then a double the distance the intensity will be 1/22 = 1/4 the initial. Triple the distance will be 1/3 = 1/9 the original and quadruple the distance will be 1/42 = 1/16 the original.
1/22 = 1/4
1/32 = 1/9
1/42 = 1/16
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