Posted by Muhammad on Saturday, April 24, 2010 at 8:16pm.
Find the distance (measured in earth radii, RE) from the center of the earth to a point outside the earth where the acceleration of gravity due to the earth is exactly one ninth of its value on the surface of the earth.

physics  bobpursley, Saturday, April 24, 2010 at 9:08pm
F=k/r^2 Since F is 1/9, it is apparent that r must be 3re

physics  Damon, Saturday, April 24, 2010 at 9:10pm
g(r) = constant *1/r^2
at r = 1 , g(1) = g
so
g(r) = g/r^2
g(r) = g/3^2 if r = 3
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