Posted by sam on Saturday, April 24, 2010 at 8:05pm.
Let the rowing rate be x mph
let the current's rate by y mph
going with the current, will be a rate of x+y mph
going against the current would be x-y mph
so you get two equations, using Distance = rate x time
1.5(x+y) = 12
4(x-y) = 12
1st: divide by 1.5
---> x+y = 8
2nd: divide by 4
---> x-y = 3
add them
2x = 11
x = 5.5 mph
back in 1st, y = 2.5 mph
so the rowing speed is 5.5 mph,
the current's speed is 2.5 mph
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