Balance the chemical equation given below, and determine the number of grams of MgO needed to produce 15.0 g of Fe2O3.
_MgO(s)+_Fe(s)->_Fe2O3(s)+_Mg(s)
1. a. 11.4 g
2. b. 3.78 g
3. c. 1.26 g
4. d. 0.0877 g
I got equation balanced 3,2,1,3 just having trouble on how to find number of grams needed
Your equation is ok.
Convert grams Fe2O3 to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles Fe2O3 to moles MgO.
Now convert moles MgO to grams. g = moles x molar mass.
Balance the chemical equation given below, and determine the number of grams of MgO needed to produce 15.0 g of Fe2O3.
To determine the number of grams of MgO needed to produce 15.0 g of Fe2O3, we need to use the balanced chemical equation and stoichiometry.
The balanced equation is:
3 MgO(s) + 2 Fe(s) -> 1 Fe2O3(s) + 3 Mg(s)
From the equation, we can see that the stoichiometric ratio between MgO and Fe2O3 is 3:1.
We can use this information to set up a proportion:
(15.0 g Fe2O3 / 1) * (3 mol MgO / 1 mol Fe2O3) * (40.31 g MgO / 1 mol MgO) = x g MgO
Simplifying the equation:
(15.0 * 3 * 40.31) / (1 * 1) = x
x ≈ 1813.35 g MgO
Therefore, approximately 1813.35 grams of MgO are needed to produce 15.0 grams of Fe2O3.
None of the provided answer choices are correct.
To determine the number of grams of MgO needed to produce 15.0 g of Fe2O3, you can use a stoichiometric calculation based on the balanced chemical equation.
The balanced equation is:
3MgO(s) + 2Fe(s) -> Fe2O3(s) + 3Mg(s)
From the balanced equation, we can see that 3 moles of MgO are required to produce 1 mole of Fe2O3.
First, calculate the molar mass of Fe2O3:
Fe2O3: (2 x Atomic mass of Fe) + (3 x Atomic mass of O)
Fe2O3: (2 x 55.845 g/mol) + (3 x 16.00 g/mol) = 159.69 g/mol
Next, convert the given mass of Fe2O3 to moles using its molar mass:
Moles of Fe2O3 = Mass of Fe2O3 / Molar mass of Fe2O3
Moles of Fe2O3 = 15.0 g / 159.69 g/mol
Now, using the stoichiometry of the balanced equation, we can calculate the moles of MgO needed:
Moles of MgO = Moles of Fe2O3 x (3 moles MgO / 1 mole Fe2O3)
Finally, convert the moles of MgO to grams using its molar mass:
Mass of MgO = Moles of MgO x Molar mass of MgO
To find the correct answer, substitute the calculated values into the equation and check which option matches the result.
Therefore, based on the calculations, the correct option would be a. 11.4 g of MgO is needed to produce 15.0 g of Fe2O3.