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November 25, 2014

November 25, 2014

Posted by **yedid** on Friday, April 23, 2010 at 11:38pm.

- calculus I -
**Reiny**, Saturday, April 24, 2010 at 10:51amSo first of all

y' = 6x^2 + 6x - 6

y'' = 12x + 6

for local max/min y'=0

6x^2 + 6x - 6 = 0

x^2 + x - 1 = 0

x = (-1 ± √5)/2

sub that into the function to get the max/min, you do the arithmetic.

for pts of inflection, 12x+6=0

x=-1/2

sub that back into the function to get the point of inflection. You do the arithm.

for concave up y'' > 0, for down y'' < 0

for 12x+6 > 0 concave up, or x > -1/2 concave up

for 12x+6< 0 concave down, or x < -1/2 concave down.

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