The masses of 4He, 6Li, and 10B are 4.0015, 6.0135, and 10.0102 amu respectively. The fission of a boron-10 nucleus into He-4 and Li-6 would ?

1)need more info
2)absorb energy
3)evolve energy
4)result in no energy change?

See how the masses add up; i.e., is B-10 greater than the combined masses of H-4 and Li-6

so there is no energy change?

If there is a difference in mass, yes, there is an energy change. If not, no, there is no energy change.

To determine whether the fission of a boron-10 nucleus into helium-4 (He-4) and lithium-6 (Li-6) would absorb or evolve energy, we need to compare the total mass before the reaction to the total mass after the reaction.

The conservation of mass in a nuclear reaction states that the total mass of the reactants must equal the total mass of the products. In this case, the reactant is boron-10 (B-10), and the products are helium-4 and lithium-6.

The total mass before the reaction is the mass of B-10, which is 10.0102 amu.

The total mass after the reaction is the sum of the masses of He-4 and Li-6, which are 4.0015 amu and 6.0135 amu, respectively.

Adding the masses of He-4 and Li-6 gives us 4.0015 amu + 6.0135 amu = 10.015 amu.

Comparing the total mass before and after the reaction, we can see that they are not equal. The total mass after the reaction is slightly larger than the total mass before the reaction.

According to Einstein's mass-energy equivalence principle (E = mc^2), a change in mass corresponds to a change in energy. In this case, since the total mass after the reaction is larger than the total mass before the reaction, it means that mass has been gained. Therefore, energy has been absorbed in the fission process.

Hence, the correct answer is 2) absorb energy.