Sunday
March 26, 2017

Post a New Question

Posted by on .

Solve the quadratic equation.

3x^2-15x+18=0

I know that the formula to quadratic equation is x=-b+and-(square root)b^2-4ac divided by 2a.

I know that a=3, b=-15 and c=18, then subsitute in and get two answers, my problem is that I keep getting an answer that does not work after I subsitute in the original equation. What do I do?

  • Algebra - ,

    did you get
    x = (15 ± √(225 - 4(3)(18) )/6 ?
    = (15 ± √9)/6
    = (15 ±3)/6
    = 3 or 2

    we could have divided the original equation by 3 to get
    x^2 - 5x + 6 = 0
    now it factors
    (x-3)(x-2) = 0
    so x = 3 or x = 2

  • Algebra - ,

    I got 3 and -2. But to check it, wouldn't you substitue it the 3 and then the -2 in the original equation and it should be 0=0?

  • Algebra - ,

    and so it does
    How did you get -2?
    if you had a + and a - then you couldn't possible end up with +18 at the end.

    if x= 3
    3(9) - 45 + 18 = ??

    if x=2
    3(42) - 30 + 18 = ???

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question