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March 30, 2015

March 30, 2015

Posted by **Anonymous** on Thursday, April 22, 2010 at 9:12pm.

- calculus -
**Reiny**, Thursday, April 22, 2010 at 9:46pmVolume = [integral]πy^2 dx from to 1

= π[integral](4+x^4)dx from 0 to 1

= π [integral] (16 + 8x^4 + x^8)dx

= π [16x + (8/5)x^5 + (1/9)x^9 from 0 to 1

= π(16 + 8/5 + 1/9 - 0)

= 797π/45

- calculus -
**Anonymous**, Friday, April 23, 2010 at 12:37amThank you sooo much.

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