Posted by **Jake** on Thursday, April 22, 2010 at 8:19pm.

what is the y value of the vertex f(x)=x^2+6x+5 I have an answer of 4 this is important because I come up with -4 and I believe the answer to this is 4

- college algebra -
**Reiny**, Thursday, April 22, 2010 at 9:50pm
we could complete the square

f(x)=x^2+6x+5

= x^2 + 6x + 9 - 9 + 5

= (x+3)^2 - 4

so the vertex is (-3,-4), so you were right

short-cut way:

the x of the vertex is -b/(2a) = -6/2 = -3

f(-3) = 9 - 15 + 5 = -4

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