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October 26, 2014

October 26, 2014

Posted by **Jennifer** on Thursday, April 22, 2010 at 4:57pm.

y=-2x^5+x^3

- Math -
**Reiny**, Thursday, April 22, 2010 at 6:04pmno estimation needed for y-intercept, let x=0 then y = 0

for x-intercept, let y = 0

-2x^5 + x^3 = 0

x^3(-2x^1 + 1) = 0

x = 0 or x^2 = 1/2

so x = ±1/√2

as x ---> +big, y ---> - big

as x ---> - big, y ---> +big

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