Posted by Jennifer on Thursday, April 22, 2010 at 4:57pm.
no estimation needed for y-intercept, let x=0 then y = 0
for x-intercept, let y = 0
-2x^5 + x^3 = 0
x^3(-2x^1 + 1) = 0
x = 0 or x^2 = 1/2
so x = ±1/√2
as x ---> +big, y ---> - big
as x ---> - big, y ---> +big
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