Saturday

August 30, 2014

August 30, 2014

Posted by **Nathan** on Thursday, April 22, 2010 at 1:27pm.

- Pre Calculus -
**Reiny**, Thursday, April 22, 2010 at 1:48pmwork on the right side

RS = 1/cos(π/6 - x)

= 1/)cosπ/6cosx + sinπ/6sinx)

= 1/(√3/2cosx + 1/2sinx)

= 2/(√3cosx + sinx)

did you make a typing error?

I tested your equation for some value of x, it did not work out, mine did.

**Related Questions**

Pre Calculus - Solve the inequality sinx>square root x.

Pre-Calculus - How would you prove/Verify this Identity. x=theta (cosx+sinx-sin^...

pre-calculus - What is the polar form of the equation 3x - 4y = 12? The answer ...

Trig........ - I need to prove that the following is true. Thanks (cosx / 1-sinx...

Trig Help - Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx...

Pre-Calculus - (not sure how to type square root of) square root of 3x - 4 = (x-...

circular (trigonometric) functions - hi, i need help solving this trigonometric ...

Pre-Calculus - I think I need help with this problem- 3+ square root(x-6) = ...

Pre Calculus - square root of 3x-4 = (x-4)^2-3 Normally, I either take the ...

Math - 1. Find y'(x) when xsecy - 3y sinx = 1 a) (3ycosx - sec y) / (xsec^2y - ...