How many liters of a 5% (m/v) glucose solution would it take to obtain 32g of glucose?
5 percent means 1/20
32g=.05*1000*Number Liters.
I don't understand what you mean at all
number liters= 32/(.05*1000)
To determine the number of liters of a 5% (m/v) glucose solution needed to obtain 32g of glucose, we need to understand the relationship between the concentration, mass, and volume.
Let's break down the process step by step:
Step 1: Understand the concentration of the glucose solution.
The concentration is given as a 5% (m/v) glucose solution. This means that 5g of glucose is present in 100ml of the solution.
Step 2: Calculate the mass of glucose in 1 liter of the solution.
Since 5g of glucose is present in 100ml of solution, we can calculate the mass of glucose in 1 liter (1000ml) of the solution.
The calculation is as follows:
(5g glucose / 100ml solution) * 1000ml = 50g glucose
Therefore, there are 50g of glucose in 1 liter of the 5% (m/v) glucose solution.
Step 3: Determine the volume of the solution needed to obtain 32g of glucose.
Divide the desired mass of glucose (32g) by the mass of glucose in 1 liter of the solution (50g) to find the corresponding volume.
The calculation is as follows:
32g glucose / 50g glucose = 0.64
Therefore, it would take approximately 0.64 liters (or 640ml) of the 5% (m/v) glucose solution to obtain 32g of glucose.