Posted by **B.B.** on Thursday, April 22, 2010 at 7:05am.

Did I do this problem right?

Divide.

x^2+4x-48/x+8

Here is how I solved this problem:

x(x+4)-48/x+8

(x+4)-48/8

(x+4)-6

x+4-6

x=2

Is this correct?

Thanks.

- Math -
**Reiny**, Thursday, April 22, 2010 at 8:24am
Sorry to say this, but looking at that "solution" made me shudder.

the correct way ... assuming you meant:

(x^2+4x-48)/(x+8)

Using long algebraic division, one gets

x - 4 with a remainder of -16

or you can use synthetic division to arrive at the same answer.

(x^2+4x-48)/(x+8) = (x-4) - 16/(x+8)

study this example

http://www.mathsrevision.net/alevel/pages.php?page=1

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