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Math

posted by on .

Did I do this problem right?
Divide.
x^2+4x-48/x+8
Here is how I solved this problem:
x(x+4)-48/x+8
(x+4)-48/8
(x+4)-6
x+4-6
x=2
Is this correct?
Thanks.

  • Math - ,

    Sorry to say this, but looking at that "solution" made me shudder.

    the correct way ... assuming you meant:

    (x^2+4x-48)/(x+8)

    Using long algebraic division, one gets

    x - 4 with a remainder of -16

    or you can use synthetic division to arrive at the same answer.

    (x^2+4x-48)/(x+8) = (x-4) - 16/(x+8)

    study this example

    http://www.mathsrevision.net/alevel/pages.php?page=1

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